Subtracting Hexadecimal Numbers: 5ED4 - 07A4 = 5730

School: York University - Course: EECS 2021 - Subject: Accounting

3.1: 5ED4 - 07A4 5370 5 - 0 = 5, E - 7 = 7, D - A = 3, 4 - 4 = 0 5ED4 - 07A4 = 5730 Assuming 16-bit unsigned hexadecimal, 5ED4 in binary is 0101 1110 1110 0100 2 07A4 in binary is 0000 0111 1010 0100 2 -07A4 is 2-s complement of 07A4 in binary, which is 1111 1000 0101 10112+ 1 2 1111 1000 0101 1100 2 0101 1110 1110 0100 + 1111 1000 0101 1100 1 0101 0111 0011 0000 2 Discarding the leftmost bit because of 16-bit limit, we get 0101 0111 0011 00002, 5730 in hexadecimal

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