What is the major organic product of the following reaction? Biz SH 'SH Select one:
Expert's Answer
In this question, we have been given a compound which is 3 methyl 3 methyl butane butane thin. Now this compound is made to react with b r 2 and we have to identify the major product. Let us look at the mechanism of this reaction mechanism. First, we have the molecule, which is 3 methyl butane, thyl, plus, b and b r. Here we can see that the sulphur atom will have 2 lone pair of electrons, and each bromine will have 3 lone pair of electrons. Now this known pair of electrons of sulphur will get transferred to this bromine, and this bond will be taken away by this bromine. Therefore, we'll get an intermediate which will be like this. Here we have the alpha with a positive charge on it, and here we have the hydrogen attached to it. Now here we have the broom with 3 lone pair of electrons, and here we have the metal group. Now, in this molecule there will be deprotonation and due to this deprotonation here we can write de protonation due to this deprotonation. The positive charge will get removed from the sulphur atom. Here we have bromine with its 3 non pair of electrons. Now, on this molecule, another molecule of 3 mutal butane theol will attack the sulphur atom having its lone pair of electrons, and it will result in the formation of this compound, which will look like here. We have ch 3 ch here we have c h 2. Here we have d with the methyl group over here, then we have the 2 lone pair of electrons and then here we have the alpha with positive charge on it and hydrogen atoms. Then here we have the parent chain now in the meantime that this thing was taking place, the double bond was transferred to the bromine atom. In this molecule there will be deprotonation and we'll finally get the final result, which will be di 3 metal, butan disulphide. This compound is known as di 3 methyl butyl di sulfide, and this here is the final answer to this question and also the major product of this reaction.
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