Given That 1 Gallon = 4 Quarts And 1 Quart = 946 Ml, Use Unit Analysis To Convert The Volume Of A 9.95-Gallon Aquarium Into

Transcribed image text: Given that 1 gallon = 4 quarts and 1 quart = 946 ml, use unit analysis to convert the volume of a 9.95-gallon aquarium into quarts, milliliters, liters, and cubic centimeters (1 cm3= 1 ml). Convert the final value in cmsto scientific notation. Show all of your equations with all units and all unit conversion factors. Also, show results with correct number of significant digits (three) for each step. 9.95 gallons x 4 quarts= 39.8 quarts/gallon 9.95 gallons x 3785.41ml= 37700 ml/gallon 9.95 gallons x 3.78541 L= 37.7 L/gallon 9.95 gallons x 3785.41 cm3 = 37700 cm3 Scientific notation 3.77 x 104 Suppose a rectangular metallic solid measures 4.52 cm by 12.50 cm by 0.0100 cm. Find the volume in cm3. If 1 cm3= 1000 mm3, convert the volume to mm3. I 4.52x12.50x0.0100 = 0.565 cm 0.565cm? x 1000mm3= 565mm Suppose a sample of a metallic solid is dropped into a graduated cylinder with water in it, and the volume increases from 2.05 ml to 8.90 ml. Find the volume of the solid. If the solid has a mass of 18.563g, find the experimental density of the solid (d = m/V). Volume of solid 8.90ml -2.05ml= 6.85ml D=m/v D=18.563 8/6.86ml= 2.71g/ml A 50.1 g water bath is heated, and the temperature increases from 80.0 C to 100.5oC. Determine the heat in both cal and kcal absorbed by the water using Table 2.5 and the following equation: heat = (specific heat) * (mass) * (change in temperature).Use 1 kcal = 1000 cal to convert the result in calories to kilocalories.Convert the result in calories to Joulesalso, where 1 cal = 4.184). Then, convert the result in Joules (J)to kilojoules (kJ), where 1 k) = 1000 J.Show all of your equations, including all of the units and conversion factors. Also, show all results in scientific notation with correct number of significant digits. 4182J/kgk * 0.0501 kg x 20.5= 4295.12 ) to Kl = 4.295K) 4295.12x1/4.184) = 1026.558 cal or 1.027 kcal Use Table 2.4, along with the density equation (d = m/V), to determine the volume in cms of a 2.125 g sample of ice (V = m/d). Then, find the mass of a second ice sample that has a volume of 2.000 cm3(m = Vxd). Show all of your equations, including all of the units and conversion factors. Also, show each result with the correct number of significant digits(four). Density of ice = 0.917g/cm3 2. Density of ice=0.917g/cm3 1. Mass of ice 2.125g V=2.000cm3 V=2.125g/0.917g/cm3 2 cm x 0.917g/cm3 = 1.834 g V=2.317 cm